10-05: input two number and display the result

Question

Write a program that let the user input two number and displays the result as the example below:

輸入兩個數字，做加減乘除的運算

Example input 1:

5 6

Example output 1:

5+6=11
5-6=-1
5*6=30
5/6=0.833333

Example input 2:

1.23 3.45

Example output 2:

1.23+3.45=4.68
1.23-3.45=-2.22
1.23*3.45=4.2435
1.23/3.45=0.356522

Remember: Your output maybe 100% correct, but your code matters!

Answer 1

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#include <stdio.h>
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Comments

Case 0: Correct output
Case 1: Correct output

Answer 2

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Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 3

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Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 4

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Comments

Case 0: Correct output
Case 1: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output

Answer 5

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#include <stdio.h>
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Comments

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output

---

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output

Answer 6

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#include <stdio.h> 
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Comments

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output

---

-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output

Answer 7

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Answer 8

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Comments

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output

Answer 9

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#include <stdio.h>
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Comments

prog.c: In function 'main':
prog.c:4:20: error: unused variable 'd' [-Werror=unused-variable]
    float a , b, c, d ;
                    ^
prog.c:4:17: error: unused variable 'c' [-Werror=unused-variable]
    float a , b, c, d ;
                 ^
cc1: all warnings being treated as errors

---

prog.c: In function 'main':
prog.c:4:20: error: unused variable 'd' [-Werror=unused-variable]
    float a , b, c, d ;
                    ^
prog.c:4:17: error: unused variable 'c' [-Werror=unused-variable]
    float a , b, c, d ;
                 ^
cc1: all warnings being treated as errors

Answer 10

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#include <stdio.h>
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Comments

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output