0 like 0 dislike
597 views

請設計一個程式,使用者會輸入一個字串,字串的內容只會包含大小寫的英文字母,並且用兩相鄰英文字母的「距離」當做作密碼。

提示1:「距離」利用ASCII碼所對應的來計算 例如R=82, O=79, 82- 79= 3

提示2: 所有小寫字母轉為大寫 a→A

 

範例輸入:

ROY
roY
ndHu
NDHU

範例輸出:

3 10 
3 10 
10 4 13 
10 4 13 
[Normal] Coding (C) - asked in 2016-1 程式設計(一)AC by (-162 points)
ID: 20514 - Available when: Unlimited - Due to: Unlimited

reshown by | 597 views

3 Answers

0 like 0 dislike
Best answer
Hidden content!
#include **** ** *** *

#include * *** *******

#include * * * ***

void test(char *t);

int main()

{
** * * * * ** *** ** ***** s[30],s2[30];
*** * ** * ** ** ** ** * ************** ** *** != EOF)
** ** ** * * * ** ** ***** *** * * * * *



}

void test(char *t)

{
** * * * **** * **** i,result;


***** * ** ** ** * (i=0; i<strlen(t); i++)
* ** ** ** * * * ** * ** * ** * * *** *
** * *** *** ***** * *** ** ***** * * *** * ** * * ** * ** * ** * ** = toupper(t[i]);
**** **** ** * * * * * *** * * * * *********


*** ** * *** ** ** (i=0; i<strlen(t)-1; i++)
** ** *** * ** ***** *
** * * ***** *** * ** * * ******* ** ** * * * * ****** = t[i]-t[i+1];
* ******* * ** **** * * ** * * * ** *** * (result<0)
*** * ** ** * ** * * * **** * * ** * * * * ***** * * * **** ** *** ",-result);
** * * * ** *** ** ** ** * ** **** * * *
** * ** ** * ** *** * * *** * * * ** * ********* * **** * * * * ** * ",result);
* ** * * * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<string.h>

#include<ctype.h>

int main(void)

{
* *** *** *** s[100];
* * **** * **** ** **** * ** schange[100];
* * * * * ** **** *** len;
* *** ** * ***** * * i;
******** ** *** ** ** * num;
****** * * *** ** *** * ** ** ** * ***
* * ** *** **** * ** * ** ***
* * *** ** * *** *** ***** * ** *
* *** ** ** * * **
* * ** ** ** * *** ** ** * * ** * * ** ***
* ** ** **** * *** * * * * ** ** ** ** ** * ******* * **
* *** ** * ** * * * * ***** ** *** **** **
********* *** * *** * * * ** *** **** ****** * ** * ** **
* *** *** * * ******
* * * ** * * **** (i=0;i<len-1;i++)
***** * * * * * *
* ** * *** * ** ** ** ** * ** * *** ***** **** * * -schange[i];
** * ** * * * ** * * *** ** *** * * * ** * ** ** ",abs(num));
* **** *** *** * * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ***** *

#include * * ** * **

int main()

{
* * *** ** ** **** s[30],s2[30];
* ***** * ********* * ** ** ** * * * * ** != EOF)
* ** * **** * * * * *** * ** ******* * * * *



}

void test(char *t)

{
** **** **** * * **** i,result;


** * * ** *** ** * (i=0; i<strlen(t); i++)
** * ** *** ** * * * **** ** * * ***** *
* ** * *** * * ** ** * * * * * * ****** * * *** * ** **** * ******** * = toupper(t[i]);
**** *** *** * * * * * * *** **** ** *** * *


* ** * ** **** * * * (i=0; i<strlen(t)-1; i++)
************ * * **
** * * ** ** ** ****** *** *** ** * * * ** **** ***** * = t[i]-t[i+1];
* * *** * **** * * ** * * * * * ** * (result<0)
* * * * ****** * ** **** * * * ** * *** ** ** ** * ***** * ** *** * ",-result);
* * * **** ***** * ** **** * **** *** * *
* * *** * * * * * ****** **** ** * * ** ** *** * *** * * * * ** * *** ** ",result);
*** ** * *** * * ** * *

}
answered by (-162 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.132
©2016-2025

Related questions

0 like 0 dislike
3 answers
[Normal] Coding (C) - asked Jan 5, 2017 in 2016-1 程式設計(一)AC
ID: 20997 - Available when: Unlimited - Due to: Unlimited
| 603 views
2 like 0 dislike
14 answers
[Normal] Coding (C) - asked Dec 21, 2016 in 2016-1 程式設計(一)AC
ID: 19745 - Available when: Unlimited - Due to: Unlimited
| 1.5k views
0 like 0 dislike
7 answers
[Normal] Coding (C) - asked Jan 5, 2017 in 2016-1 程式設計(一)AC by 林佳慧 (-85 points)
ID: 20976 - Available when: Unlimited - Due to: Unlimited
| 798 views
0 like 0 dislike
31 answers
[Normal] Coding (C) - asked Jan 3, 2017 in 2016-1 程式設計(一)AC
ID: 20482 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
5 answers
[Normal] Coding (C) - asked Dec 27, 2016 in 2016-1 程式設計(一)AC by 410342026 (-105 points)
ID: 20135 - Available when: Unlimited - Due to: Unlimited
| 989 views
12,783 questions
183,442 answers
172,219 comments
4,824 users