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AC 20161207 exercise 1
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子字串
請設計一個程式，使用者會輸入兩個字串，兩個字串間用一個空格隔開，每個字串的內容只會包含大小寫的英文字母，請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。
輸入範例1：
friEND end
輸出範例1：
There is "end" in "friEND"
輸入範例2：
friEND friends
輸出範例2：
There are no "friends" in "friEND"
asked
Dec 7, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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Hidden content!** * * * ** * ** ***
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answered
Dec 18, 2016
by
410523016
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Hidden content! *** * * * ** * * *
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answered
Dec 18, 2016
by
410523016
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Hidden content!#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
int main()
{
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answered
Dec 18, 2016
by
Gulang
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-122
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Hidden content!#include <stdio.h>
#include * * * * * * *
#include <ctype.h>
int main()
{
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answered
Dec 18, 2016
by
Gulang
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-122
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
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* * * ** ** *** * ** * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
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** * **** * * * * ** * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
* * * * * * *
#include<ctype.h>
int main ( void )
{
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* * ** * * * * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * ** * * ** * * i,j;
** * * ** * * **** * *** * * * * *** * ** * * * *
** * * * * ** * ** * *** * * * * *
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* * * ** * * * * * *
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** * ** * ** * *
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* * *** ** * ** *** ** * ** * ***** *** * ** * = c2;
** * ** ** * ** ** * *
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* ** *** * * ** * * * ** * * * *
* ** * ** * * * * * * * ** * * *** * **** * * ** * ** ** * are no %s in %s",b,a);
** ** * * ** * * ** ** * ** ** *
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* * * ** * * * ** * * * ** 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* ** * ** * * * ** * * ** * * i,j;
** * ** * * * * * *** * ** * * * * *** **
***** * ** * * * * * * * * * ** * * *** * **
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* ***** * * * ** ** ** * * * * ** * ****** ** * ** ** = c1;
* * * * * * * **
* * * * ** * * * ** * *
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* * * ** * ** * **** * * * * * * **** = c2;
* * * * **** * * * *
* * *** * * ** ** ** * * * * ** = strstr(a,b);
** * *** * ** * * * ** *
* * * * * * * * ** ** * * ** * * ** * * * ** * * * ** * * * *** * are no %s in %s",b,a);
** * * * ** ** *** * * * * * *
* * ** * * * * * *** *** * * * * ** * * * *** * * * is %s in %s",b,a);
* * * * ** ** * ** * * * * ** ** * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include * ** ***
#include * * *** ** * * *
#include * * * ** *
#include ** *** * * * *
#include * * * ** *** **
int main(void){
**** * * * ** * * * * ** * * * * * *** * * ** *
***** ** **
* ** *** ** * * * * ** ** ** ** ** * *** * *
* * * * * **** * * ** * **
* * *** * * ** *** * * *
* * * * ** * * *** * * *
* ** * * *** * ** ** * * * * * (i = 0;s[i] != '\0';i++)
***** ***
* *
** * * * * * * * * * * ** * ++;
*** * * * * ** * * * * * *
}
* ** ** *** * ** * * * (i = 0;t[i] != '\0';i++)
* *
* * ** * ** ** * ** **** ** * *
* * * ** *** ++;
* * * * * * *
}
** * *** ** * * * * ** ** * * * * * * * * **
* * * * ** * * ** * ** **
** (i = 0;i <= sizes;i++)
** * *
* * * * ***
*** * ** * * ** = s[i];
* *** * ***
* * *
** * * (i = 0;i <= sizet;i++)
* ** * *
* ** * ** * * *****
* * * ** = t[i];
* ** *** *
* ** *
* * * ** ** * * * * **** **
* * * * (i = 0;i <= sizes;i++)
{
* **** * * *
*** * * ** * * **
*** ** * *** * = p[i] - 32;
* * * * *
* * * * *
** * ** * ** * = p[i];
}
* * * ** ** ** * * * ******* * ***** * *
for (i = 0;i <= sizet;i++)
{
* * *
*** * *** * *
** * *** * ** = f[i] - 32;
* * * * * *
* * **
* * *** * ** ** * = f[i];
* * *** ** * **
}
* * * *** * * ** *
//asplpSLP slp
* ** * (i = 0;p2[i] != '\0';i++)
**
* * (p2[i] == f2[0])
** * * ** ** *
* * * * * **
** ** * * * ** ****** = i;
* ** ** ** ** *
* * * * * * (u = 0;u < sizet;u++)
* * * ** * ** *
** * * ** *** * * **** * *
** * * * * ** * * * * *
* * * * * * * * *** * * *** (p2[j+u] == f2[u])
* *** * *** *** ** * ** * ** **
** * * * *** * * ** ** ** += 1;
* * * * * * ** * ** * * *
* * * *** * ** * * ** * * **
* * * * * ** *** * * * * **
* * ** * * * * * * **** * * * ***
* * * ** *** * * ** *** *** * * * ** ** **
* ** * * ** * *** * * *** * = 0;
** ** *** * * ** * * *** * ** ** * **
** * ** * * * * * * * * *
* *** * * * ** * * * * * * **
* *** *** * * *** *** * * *** * *
* ***** * * *** * * ** * * *
*** * *** * ** **
* ** * * * ** *** * *** *** ***
* ** * * * **
* * * * ** * * *
* **
** * *** * * * * * * * ** (d > 0)
* * ** * *** * ** * *
* * * ** * * * * *** ** * *** *** is * *** * ** in * * ** * * * *
*** * ***** * * * ** *** * * * * **
* * ** * * * * * ** *
* * * ** *** ** * * * *
*** * * * * * * * * * *** * * * * are no * * ** * * * * * in * * ** * ** * **** * * *
** * * * **** * ** *** * 0;
** *** * ** * * * * ** * *
}
answered
Dec 10, 2016
by
蘇瑋朝
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