0 like 0 dislike
6.2k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13736 - Available when: Unlimited - Due to: Unlimited
1 flag | 6.2k views
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help

61 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main()

{
** ** * ** * ** **** n,j,k;
* * * **** * * ** ******* * *** ***** *** *
** ** * **** ** *** * ** * ***** ***
** * * *** * ****** ****
* ** * * ** ** * * * *** ** * * ** * *** ** *** * * * *
***** ** * *** *** * * * * ** * * * **** * ** * *** ");
*** * **** **** ** * * ** **** *** * *** *** * ** *
***** * *** * * * * ** ** *** ***** * * ** **** *** * * * ** * * * *
* ** *** ** *** * ** * * ** * *** * ** * * * * *** * ******

    }
* * * ***** * * **** * 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * ** ** *** *** * *
***** ** * ** **



int main()

{
* *** * **** * n, j, k;
* *** * ** * ** ** * ** *** ** ** * &n);


** ** * ** * * * * * * * = 1; j<= n / 2 + 1; j++)
* ** ** *** **** *
* ** * ** ** **** ****** ** ** = 0; k < n / 2 + 1 - j; k++)
** **** ** * *** **** * * ** ** *** * *** * * ** * **** * * ** * * * ");
***** ** *** *** * **** ** * * * * ** * * * = 0; k < (j - 1) * 2 + 1; k++)
* *** **** * * *** ** **** *** * ** * *** *** ** * **** * ***** *** ***** ** * *
* ** ******** * * *** * ** * ** ***** * *** * ** * *** * ****** **** **
***** * * * *

return 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
******** * * * *
**** * ** ***** ***


* * ***

{
**


******** * * ** **** * *


*** *** / 2 + * *
*
** **** ** ** / 2 + 1 - *




* * * * * * ***
* ** ** - 1) * 2 + *


** ** * * * **** ** ** *** **** **











** *

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include *** * **** **



int main()

{
* * ** ** *** ***** ** * n,j,k;
** ********* ** **** * * ** ** * *** * **** *
*** ** * * * * ** ** = 1; j <= n / 2 + 1; j++)
* * * * *** ** * * * *
* * * *** ***** * * * = 0;k < n / 2 +1 - j ; k++)
** * ** ** * *** * ** **** *** ** **** * ** ");
****** * * * ** ***** *** ** = 0;k < (j - 1) * 2 + 1;k++)
* * * ** *** *** * * ****** * * ** ********* * *** *
*** * ** **** ** *** * * * * * * * * * * * *** ** * **
*** * *** * *** ** *** *
**** * * ***** * * * ** * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* **** *** ** num1= 0,i=1 ,j ,k,u=0;
* * * * * * *** *** * * ** * ** ** *

   if( 1== num1%2 )

   {




* * ** * ** * * * (i<=num1)

   {
* * * ** **** **** * ** * * *** *** *** * * **** * * *
* * ** ** * * *** ** * * *** * *
** ** * * ** * * * * * ** ** **** * *** ****** * *** * ** ** ****** **** ");
** **** * **** ** * * ** ** ***** * *
* * *** * * ** * * ** ** * *** ** * * * * *** **
* * * ** **** * ** ** * ******* ***
**** * ** * ***** * * * ** * **** ** * * * * ** **** * ** ***** ***** * ** * ****
**** * * * *** *** **** * * *** ****
** ** *** *** ** ***** ** * ** **** * *** * **
* * * *** * ** * * ******* * ** ** ** **
*** ** ** * ** * * ** ** * ** *** * **
*** * * **** * *

   }
* * ** *** ** * *** ** 0 ;



}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main(void)

{
* * ** * n,i,s;
* * ** * * * *** * *** * *** * ** * * * ** *
**** *** * * ***** ** && n/2 != 0;
* * *** * * * **** * * ***** * *** * * ** * (i=1;i <= (n/2)+1;i++)
****** * * ** ** * *
* ** * * *** ****** ** * * * * *** ** ** ***** (s=0;s< n/2+1-i;s++)


*** * * *** ** * * * ** * * ** ** *** **** **** * ** * * * ** * *** **** * * * ** * * *** * ** *** ");


*** ** *** * *** * * * ****** **** * *** * ****** *** * * ** * **


*** * ***** * *** ** ** ** * * *** **** ****** ** ** *** ****** * *** **
** * * *** *** **** * * ** * *** * *** * *** * * ******* * **** *** * * **** *
* * **** * * * *** *



return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * * ** ** * * *



int main()

{

int **
* ** ******* **** ** *** *
* * = **** * *

{
***** * **** /2 +1 -j ;k++)
* ** * * ** * * * * * * * *
* * ***** **** - ****
* * * *** * * ** **** **
**** * *** * * *

}
* * 0;

}
answered by (-50 points)
0 like 0 dislike
Hidden content!
** *** * ** * *



int main()

{
* *** ****** ** **** * n, j, k;


* * * * **** ** * * *** , &n);
** * ** * *** ** = 1; j <= n / 2 + 1;j ++)
* ** ** *** *
* * * ** ** * * * ** * * * ** = 0;k < n / 2 + 1 - j;k ++)
** * * * ** * * ** * * * *** ** * * ** *** * **** * ");
******* * ******* *** ** ** ** ****** *** ** < (j-1) * 2 + 1;k ++)
* *** * ** *** * * *** ** ** *** * *** ** * * *** * *** * *
** * * *** * **** * * * * * ** * ** * * * * * *** * **
* * * ** * *
** ** * * * * ** 0;

}
answered by (-90 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
*** * *** ****** ** ** num1= 0,i=1 ,j ,k,u=0;
* *** * * *** ** * ***** ** ** **** **
***** *** * * * * 1== num1%2 && num1<=20)

   {




** * ** **** *** (i<=num1)

   {
* * * * * * **** * * * * ** * **** ** * * * ******* *
* * * **** ** * * * ***** * * * *
* * * * * * **** ** * ****** ** * ** * ** * *** * ** * * * ** * * ");
* * ***** * ** * ** * ** ** * * * **
** **** *** ** ** * * *** * * * *** *
******** * * * * *** * ** * * *** *
* ** *** ** ***** ** * ** * ** * * * * *** * * *** * **** *
*** * * ** ** * ** * *** * * ****
* ** ****** ** ** ** ** * * * **** ** * *
* ** * ******* **** ** ** ** *
**** ** ** *** * * * * *** * * ** * * * **
** * * * * * * * ****** ** ***** **

   }
***** * ** *** * * * ** 0 ;



}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(void)

{
* * * * * * * *** n,j,k;
* * ****** ** *** *** *** * * * *** ** ***
* * ** * ** ** ** * = 1;j <= n / 2+1;j ++)
**** * * ****
* ***** * ******* *** * = 0;k < n / 2 + 1 -j;k ++)
* ** ******** *** * *** ** *** *** * ****** * ** * * * ");
** * * * ** * * * ** *** ** * * * * **** = 0;k < (j - 1) * 2 + 1;k ++)
* *** ** ** * ** * ** * *** * * ** * ** * * *** * ** *** ** ** * *
**** * *** ** *** * ** * ** * ** * ** ** ** * *** **** ** *** ** * * **** * * *


* *** * ** * *
** * * **** * * * 0;



}
answered by (-8 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.239
©2016-2025

Related questions

0 like 0 dislike
64 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13763 - Available when: Unlimited - Due to: Unlimited
| 5.9k views
0 like 0 dislike
91 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13617 - Available when: Unlimited - Due to: Unlimited
| 8.3k views
0 like 0 dislike
117 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13581 - Available when: Unlimited - Due to: Unlimited
| 9.7k views
0 like 0 dislike
152 answers
[Exercise] Coding (C) - asked Oct 5, 2016 in 作業 by Shun-Po (18k points)
ID: 12295 - Available when: Unlimited - Due to: Unlimited
| 12.7k views
1 like 0 dislike
48 answers
[Exercise] Essay (Open question) - asked Nov 2, 2016 in 作業 by Shun-Po (18k points)
ID: 16865 - Available when: Unlimited - Due to: Unlimited
| 5.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users