[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include *** ** **   **

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  * *   *    **
#include ************ * *

int main() {
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* *  *  **   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *** * **** * *** *
#include  *** ** *   *

/* run this program using the console pauser or add your own getch,   ** * *** ** ** * **** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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** ***   *    ** 
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int main(int argc, char *argv[])
{
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*  *  *      *   ** ** *   * *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
    *** *******    ***       * **  * *  *  
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * * ***** ***   *  *  * 
**     *** *** ***      
int main(int argc, char *argv[])
{
* *** *    *   ** *    *     * i, a;
* * * *   *  *  * * *  **** * **      **** *  your input:");
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 * ** *  ** ** ***** * *        * ** * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 *  **    *  **   
****   ** ** * *   *  **
int main(int argc, char *argv[])
{
** ***   ** * * *** ****  i, a;
 **  *****  * * * * ** *      **  ** ***  your input:");
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* *  *** *      *  *  *  ***  (i=1)
***    ** ***    ******* ***** *     ***  * ****       ***  *  * *   ** * * * 
  *  *  * *** ** *     *  ***    **   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* ** *   *   * *  * 
*   * **** **    **

int * *** argc, char ** *  {

* *  *  *** *    int a=10;

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    ****   *   *   ******  ****     **  ** **  *** *   **  *  *
*****   *  **** **  *    ** * 
** **  ** *    *   a != 10 );
  *    ** **  * * 
    *  ** **   *  **** ***  9 8 7 6 5 4 3 2 ***  ** * **
* * **  *   *** *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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** ***   ***  *   ** * * *

int  ** argc, char ***   {

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** * *  *  *****  *  ** * * *  * if( a   *** 10)
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* * *  ****  **   *** * *   ** **  
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**  ** *  ** * ** **       * **   * * *  *  *          ** ****   **     is too high! *  ***  
*** *   *** *   **  a != 10 );
  **  ** ** *    
*  ** *   ****    * **** * 9 8 7 6 5 4 3 2 *  ** ***  
     *   ** **** **  * * 0;
}

Comments

Case 0: Wrong output