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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 1.2k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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* * * * * ***** * *** *

* * * * * * * ** * * ** ****** *** * * *
** * ** * ** * ** * * 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include * * * *
int main(int argc, char *argv[]) {


* * * ** * ** char a;
* ** * **** ** *** **** b;
* ** * ** ** ***** * c;
* * ** * * ** * ** d;
**** *** * * * * * e;
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* * * **
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}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
int main(int argc, char *argv[]) {


* *   char a;
** * ***** * ** ** * b;
**** * ** * * char c;
* ******* * * ******* d;
** * * *** ** ** * ** e;
* * ** * * * *** ** ******  
    * * ** ** %c %c %c %c ********** ** ** * * * ** **** * * ** ** ** *
** *  
    ** *** ******* * ** * * * ** * ** ** ** ******** * ** *** *********** *
* * ** ** ** ***** * **
* ***   ** * ** *** * **
* *** * * ***** *
* ** * * **** ** **** * *
** * * * * *** ** *****
*** * * ** * *** *** ** * ** ** *** *
** ** **** *** ** ***** ** *
***** *** * ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
*** *** **** **

* * * * * * * **** {

* *
* = * *
= * * * *
= * **** *
* = * **
* = ** ** *

e =
= **
* = ***
=

**
***
* *
** *****
* *

*** * * ***** *** * * *
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* ********* **

* * ** ***** {

** *
* = ** * * *
* = *
* = *** *
= * *
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e = *
=
= ***
= *

* **
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** *
*** **
** *

*** **** ****** **** ** * *
*
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * ** **** *
#include * * *** ** * **

int main(int argc, char *argv[]) {
* * *** ******** * ** * letterj;
**** *** **** ** **** ** ** *** letteri;
* * ** *** ** ** * * *** letterm;
* * * * * * * * * * ** lettere;
* * * ***** * *** lettern;
* * ** *** * * * ** *
*** **** *** * ********* *** input the letter to encode: ");  
* * ********* * *** * **
* * ** * ** **** * ** **** * ** * &letterj, ******* * &letterm, *** ** ** * ***** ** **
*** * *** **** *** *** * ** * +3;
* ** *** ** * ** ****** * ** * +3;
*** * * * ** * *** * ** * ** +3;
* * * ** * ** * * ** * * * +3;
*********** **** *** * ** +3;
*** * * * * * * ***** *
** * ** ** *** * *
* * **** * *** * *** * * * * * * * ** * * ** ** * lettere, lettern);
* * *** ****** *** * * *
* * * * ** **** ** * * 0;
}


INPUT
*** ** **
* **
OUTPUT
* ** * * *
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
*** ** * * * ***

int * ** argc, char * {


** * *** char a;
* *** * ** *** ** ** * * * ** ** char b;
* ** * * * *
* ** * ** * * *** * * **** * * **
* * ** * * * *
*** ** * * ** the ** * how??
*** * ** * ***
* **** * * *** ***** ** *** **** ** a,b);
** *** **
**** ** * ** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include **** * * *

int main(int argc, char *argv[])
{
*** *** *** * letterj;
* * * * *** ** * * * letteri;
* ** **** * ** ** ** * ** * letterm;
** ** *** * ***** *** * lettere;
* * *** * * *** ** * * *** * ** lettern;
**** ** * * **
** **** * * *** *** * ** ** ** * * * input the letter to encode: ** * ** **
* * * * * * * * * * ** * * * **** *** ** * * ** ** ** * * * ****** * ** ** *** ** ** *** *
* ** * * ****
* *** * ** ** ** * **** ****** = letterj +3;
* *** ** * * *** * * ** = letteri +3;
****** * ** * **** *** ** = letterm +3;
* ****** ** **** ***** = lettere +3;
* *** ** ** * * *** * = lettern +3;
** * ** * ** * * ** * *
** *** * * * ** *** * * ** ** ** * *** * * *** * ** lettere, lettern);
* * ** ** *

******** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* **** ***

* * ** **** ** * ** {

* * ***
* = ** ** **
= ** *
i = * * **
* = ***** *
= ** **
e = *
** = **
* = * *
* =

** *
* **
*** *
* * *
* * **

* ** ****** * ** **** *****
**
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** * ** **
#include * * ** **

int main(int argc, char *argv[]) {
*** ** ******* * *** * * * letterj;
* **** *** * * * * ** ********* letteri;
** *** *** * ** ** letterm;
* ** *** * * *** lettere;
* * * ***** ** *** **** lettern;
* * * ***** * **** ***
* * * ***** ** * * **** * input the letter to encode: *  
* * * ** ** * * * * ** *** *** * ** ** * * ** ** * * ** * ** * * * ** * ** *** * ** **** * * **** * *
* ** * * ** **
* * * ** letterj = letterj +3;
** ** * ** ** * ** ** * * = letteri +3;
* * * * ** * * * ** = letterm +3;
* * * * ** * * *** **** = lettere +3;
* ** * ** **** * *** * = lettern +3;
** * * * * ** *
* ** ** *** * **** * * ***** ** * *** * * ** ** ******* ** * ***** * ** lettere, lettern);
* * * * * *
* **** ** *** * * * * 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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