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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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20 Answers

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int ***** * * * *** a){
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answered by (-122 points)
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Hidden content!
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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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}
answered by (-8 points)
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Hidden content!
** ** ** **** ** *



struct Student {
** * * ** * * * grade[20];
** ** * * ** **** * ** * count;



};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


******* * * ** grade[20];


* **** ** *** ** * count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
* *** *******

** ** * ****

* * * **



struct student

{

* ** ** *** * * grade[20];

* *** **** * * count;

 };



int **** * ** student s);



int main(void)

{

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int **** * * student s)

{

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* * *** **** *** ** ** * = sum + s.grade[j];

* * ** *** ** * * ** ** * ** = sum/s.count;

* ** * * ** *** * * ** average;

}
answered by (-102 points)
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Hidden content!
*** ** * ** * *
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** ** * **



struct Student

{
** ****** ***** * ** * * ** grade[20];
*** **** ** * ** **** ** count;

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int * ** *** Student s);



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{

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}



int * * * *** * * Student s)

{
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*** * * ****** ** * * = b+s.grade[k];
* * * * * ** *** * * * = b/s.count;
** * **** * * *** * **** *** *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * *** * *

struct student

{
* * *** ** ** *** * *** grade[20];
** * **** ** ** ** ** count;

}s;

int main(void)

{
* * * *** * * * ** * student s;
* * * ***** * * ***** grade[20];
* ** ** *** * **** ** * count;
* ** ** * ** * **** * i;
** **** * * *** ***** ** sum = 0;
* * ** ** * ** *** **** aver = 0;
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***** * * * * * * = 1;i <= count;i++)
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*** * * * * * *** * * ** * *** ** * ** * * **** *** ** * * * *
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***** * ***** ** **
* *** ** * ** * *** ** * = sum / count;
** ** ** **** *** * * * ** * *
* * *** *** * * * ** 0;

}
answered by (-320 points)
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