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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** * * * * **** * * * *** * * a,b=0;
* * * *** * * * ** * * * * * ** * ** *
* ** * ** * ** * * * * ** * ** * * *** * = b+a;
*** * ** * ** * * ** * ** ** * ** * * ** *
* * * ** * * * * ** * * ** * * **** * *
**** * * * * ** * * * *** *
* ** ** * ** * * * * * * *** ** *
int main()
{
* * ****** ** *** * * * num;
** * * * * * * * ** * * *** ** * * * * * * ** **
* * * * * ** * **** * * ** *
*** ** * * * ** * * * * *
* ** * * * * ** * * * * *
* * * * * *** ** *** ** * * * * ** * * ***** *
* * * * * * * ** * * 0;
** * ** * ** ** * * * * **
* ** * * * ** ** * *
* * * * * * * * * *
*** *** ** * * * **** * **
** * * * * * * * *
* * * * * ** * * ** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** *** ** **** * * * i,n,fi,last1 = 1,last2 = 1;
* * ** * *** ** * * * *
** * ** ** *** * * * * ** * * * * ** * * ***** * * * * * *
* * * * ** * * * **
* ** **** * * *** * * * *** *** * * ** == 1||n == 2)
** * * * * ** * * * * *** * * * * * *** **
* * * *** * * * * * **
* *** * ** * **** * ** * * * *
* * * * *** * * * * ** * * = 3;i <= n;i++)
* ** ***** * * * * ** * * * **** ** + last2;
* ** * * * * * * * * * * *** * * * * *** ** = last1;
** * * ** * ** * * * ** * *** * ** * * * * ** ** = fi;};
* * * * *** ** * * ** * ** ***** ** * * * * *
* * * * * * ** ** * * ** * *
* * * ** * *** * * * ** * * ** *** * * ** * * *
* * ** * * * ** ** * *** *** * ** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * * * ** * ** ** i, num1 = 1, num2 = 1, sum = 0;
* * * * *** ** ** * ((num == 1) || (num == 2))
* * ** * * * * * ** *
* * ** * ** * * * ** * * *** ** * * * *** ** * *** ** ** * 1;
** * * * * * * ** ** * ** * *
** * ** * * * * * **
* * ** * ** * *** *** * * *
** * ** * * * * * ** * * ** * * * * ** * (i = 3; i <= num; i++)
** * * ** * * ** ** * *** * * * * ** * *** * *
* *** * * * * ** * * * ** * *** * * * * * * * * * *** * * ** * ** = num1 + num2;
* **** * * * ** * * *** * * **** *** * ** * * * ** * ** * * * * * *** * ***** = num2;
* * * * * * * * * ** *** ** * * **** * ** * *** ** * * * * * * ** * *** ** ** ** * **** = sum;
* ** ** * ** * * * * * * * * * * ** * *
* * * * * * ** ** * ** * * * * **** * *** *** * sum;
* * * * * * * * * ***
}
int main()
{
* * * *** * * * ** num, sum;
***** ** * * * * * ** * * * ** * * * * * &num);
* ** * * * * * * * = sumNfiS(num);
** * * * ** ** * * * * ***** *** ** * * * * * sum);
** * * * *** ** * * * * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * * * * * * * * * * int num;
* ** * * * ** ** a,n,b=1,c=1;
* ** * ** ** * * ** * * * * * * * * *
* * *** ****** * * * ** ** *** ** *
{
* * **** **** * ** *** * * ***** * ** *** * * * **
* ** * * * * * * * ** * *** * * * ** ** * * * * * * * *
}
* * * * * * *** ** * ** * * * *
{
* * * * * * **** * **** * *** * * ** * * * * * * ** * * *
* **** *** * * * * * * *** * * * ** ** *** * * *
* * **** ** * * ** ** * * * *** * * **** * * * ** ** * ** * ***** * * ** *
* *** *** * ** * * * * * * * ** * ** ** ** * * * * ** *** * * ** *
* * * * * ** * *** * ** * * * * *** * ** * * * * * * * *
*** *** ** * * * * * ** * * * * ** *
* *** * * * * * * * ** * *** * ** * * *** * ** * * ** * ** ** * *
}
**** * * * ** * ** * * ** * ** ** * **
*** * * * *** * * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * * * ** ** * * * * ** i, num1 = 1, num2 = 1, sum = 0;
* ** *** * * *** ** **** ((num == 1) || (num == 2))
* *** * * ** ** * * **
* * *** * * * * * * * * * ** * * ** * * * * **** * 1;
* ** * * * * ** ** ** *
* ***** ** * ** * ** *
* * * *** * ** ******** *
* * * ** ** * ** ** ** * * ** * * * * ** * (i = 3; i <= num; i++)
* *** * * *** * ** * ** * * * * ** ** ** * * *** ** * * *
*** * ** *** * * * ** * * ** * * * ***** * * * * * * *** * * ****** * * ** * * ** = num1 + num2;
** **** * * * * ** * * * ** ** * * *** * ** *** * * * * ** * *** *** * * * = num2;
** * ** *** * ** ** * ** * ** * ** * * * *** * *** * * ** ** = sum;
*** *** ** * ** ** * ** * * ******** ****** * *
* **** * * * * ** * ** * * * * * * ** ** * * * * **** * sum;
* ***** ** ** ** * ** *
}
int main()
{
* * **** *** * * * * *** * * num, sum;
* * * * *** ** ** *** **** * *** ** *** * &num);
** ** * * * * * * ** * = sumNfiS(num);
* * ** ** * * * * * * * * * * ** sum);
** * * * *** * * * * * * ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* **** *** *** ** * **
#include<math.h>
int main()
{
** * * * * * * * * * i,j,k=0,a=1,b=1;
** ** ** **** *** * * * * ** * *** * * ** *
* * * * * * * * * ** * * *** * || i==1)
* * ** ** * * **** * * * * ** ** * *
* *** * ** ** * **
{
* * * ** * * * * * * * **
{
* * * **** *** * * * *
* ** * *** ** * ** ** ** **
** * * * * * * * * *
}
***** * * * ** * * * * * * ***** *
}
* * ** ** **** * * * *** 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * ** * k, num1, num2, i;
* * * * * ** ** * * ** = 1;
* * * * * * * = 1;
* * * * * * ** == 1 || x == 2)
* * * * * * * ** * * ** * ** *** ** * * * **
** * * * * * *** **
** * **** ** * *
* * * * *** * *** *** ** * * * ** ** = 3;i <= x;i ++)
*** ** * * **** ** * * * * *
** * ** *** * * * * * * * ** * ** ** *** * * * * * ** = num1 + num2;
** * ** * ** ** * * * * *** * * * * * * * * * ** * = num2;
* * * ** * * ** * ** * * * **** * * * * * * * *** * * * * * = k;
** * ** ** ** * * * *** ** **
* * * * * ** * * * * * * * ** *** * * * k);
** * * * ** ** *
}
int main()
{
*** ** * * * * * x;
* ** * * * * ** * ** ** *** * ** &x);
* * * *** ****** ** * ** **
* * * * * * * * ** * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ** ** * * * *** * * i,sum=0;
***** * **** * * * * x=1,y=1;
* * ***** * **** * * * ** *
** ** *** * ** ** * ** ** ** *** * * * * ** * ** * 1;
*** * *** * * ** * *
* * *** ** * ** * * ** * *** * * * * * ** ** * 1;
* * * * * ** * * ***
{
** *** ** * * ** * *** * * * * * * ** * * * * * *
** * * * * ** ** ** * * **** * * ** *** *
* *** * * * * * ** *** * * * * ** * * * * * * **** * * * ** ** = x+y;
* ** * * ** * * * * * ** *** ** * * * * ** * *** * * * = y;
* ** ** ** ** * * *** *** * * * ** * * *** * ** * * ** = sum;
* * * * *** * * * * * * * * *** ******
* ** * * * * ** * * * * * **
* ** * ** ** * * ** * ** * * * * * sum;
}
int main()
{
* * * * * * ** a,total=0;
* *** * * * * * * ** * * * * *** * * * * * *
* * * *** ***** * * = fas(a);
* * ** ** * * ** *** * * * ** * * * * * **
* ** ** ** ** * * * **** * * ** ** * * * *** **
* ** **** * * * * * * * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * *** * * ** * * ** k, num1, num2, i;
* ** ** * ** ** ** * = 1;
** * * * ** * ** * * = 1;
* * * * * * ** * * ** ** == 1 || x == 2)
* * *** * * ** * * * ** ** * ** * *** * *** * **
* * ** * * * *** *
** * * * * * ** * * **
* **** * * ** * ** * ** ** * * * * * * = 3;i <= x;i ++)
* * *** ** * ** * * ** *** **** * * ** *
* * * ** **** * * ** * * * ** * * ** *** = num1 + num2;
* ** * *** * * * * * * * ** * * ** * * *** * * = num2;
* * * * * * ** * *** * * * * * **** * *** ** ** ** ** * = k;
* ** *** ** * * * * * * *
** ** * * * * * * * * * ** * * * * ** ** ** * *** * *** * **** k);
** * * * ***
* ** * * * * * ** * * 0;
}
int main()
{
* ** * * * * * x;
* * ***** * * * ** * ** * * * ** * * ** &x);
* * ** ** * * * **
* * * * * ** * ** ***** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * *
#include * ** * * *
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * * ** ** * ** * ** a,b,sum;
* * * * ***** * * *** * ** * * * * * * ** *
** * * * * * * ** * * * * ** = printFF(a);
* **** ** * * * *
* ** * * ** ** *** * * * * ** * * * ** **
* *** *** * ** * * * * * ** ** * * * * * ** * ** * ** **
* * * ** ** * ** * ** * 0;
}
int printFF(int n){
*** ** ** * *** * * * * f[10000]={1,1,0},i;
* * ** * * ** * * * * **** i <= n; i++)
* * * * * * * ** * * * * * * **** **** ** ** *** * * ** * * * ** * * ** **** * * *
* * ** ** * * * ** * ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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